S3 file upload project Python-World#449

Miguel Wychovaniec · Miguel Wychovaniec · commit 3a7002825a57 · 2021-11-11T18:49:01.000-03:00
diff --git a/projects/S3_File_Upload/README.md b/projects/S3_File_Upload/README.md
@@ -0,0 +1,13 @@
+
+##Simple Python script for AWS S3 file upload.
+
+###Prerequisites
+boto3 (pip install boto3)
+
+###How to run the script
+Specify both ACCESS_KEY and SECRET_KEY. You can get them both on your AWS account in "My Security Credentials" section.
+Specify the local file name, bucket name and the name that you want the file to have inside s3 bucket using LOCAL_FILE, BUCKET_NAME and S3_FILE_NAME variables.
+Run "python main.py"
+
+###Author Name
+Miguel Wychovaniec - https://github.com/miguelwy
diff --git a/projects/S3_File_Upload/main.py b/projects/S3_File_Upload/main.py
@@ -3,6 +3,9 @@
 
 ACCESS_KEY = 'XXXXXXXXXXXXXXXXX'
 SECRET_KEY = 'XXXXXXXXXXXXXXXXXXXXXXXXXXXXX'
+LOCAL_FILE = 'local_file_name'
+BUCKET_NAME = 'bucket_name'
+S3_FILE_NAME = 'file_name_on_s3'
 
 def upload_to_s3(local_file, bucket, s3_file):
     s3 = boto3.client('s3', aws_access_key_id=ACCESS_KEY,
@@ -19,4 +22,4 @@ def upload_to_s3(local_file, bucket, s3_file):
         return False
 
 
-result = upload_to_s3('local_file_name', 'bucket_name', 'file_name_on_s3')
+result = upload_to_s3(LOCAL_FILE, BUCKET_NAME, S3_FILE_NAME)
