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silksil
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Jun 3, 2018
| const tasks = monday.concat(tuesday); | ||
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| // Add your code here | ||
| const salary = tasks |
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you could consider making the function more descriptive e.g. calculateSalary
| .map((duration) => duration * 23) | ||
| .reduce((acc, current) => acc + current); | ||
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| console.log('Maartje has earned €' + salary.toFixed(2)); |
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I personaly would move the .toFixed(2) to the function 'salary'
| .map((duration) => duration * 23) | ||
| .reduce((acc, current) => acc + current); | ||
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| console.log('Maartje has earned €' + salary.toFixed(2)); |
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you could consider to pass the tasks and salary as two arguments, something like:
const calculateEarnings = (arrayOfTasks, hourlyWage) =>
arrayOfTasks.map((task) => task.duration / 60)
.filter((hoursAmount) => hoursAmount >= 2)
.map((paidHoursAmount) => paidHoursAmount * hourlyWage)
.reduce((sum, amount) => sum + amount, 0)
.toFixed(2);
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